What is the equation of a circle with its center at (0,3) and a diameter of 6?
What do you want to find out about this circle?
I need the equation of the circle.
The multiple choice answers are:
a. x^2+(y+3)^2=9
b. x^2-(y-3)^2=9
c. x^2+y^2-6y=0
d. x^2+(y-3)^2=0
e. x^2+(y-3)^2=36
I don't know where to go from here.
See:
http://www.jiskha.com/display.cgi?id=1252375294
To find the equation of a circle with its center at (h, k) and a diameter of d, we can use the standard form equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) represents the coordinates of the center, and r represents the radius.
In this case, the center of the circle is (0, 3) and the diameter is 6. To find the radius, we can divide the diameter by 2:
radius = diameter / 2 = 6 / 2 = 3
Now we can substitute the values of (h, k) and r into the standard form equation:
(x - 0)^2 + (y - 3)^2 = 3^2
Simplifying further:
x^2 + (y - 3)^2 = 9
So, the equation of the circle with its center at (0, 3) and a diameter of 6 is x^2 + (y - 3)^2 = 9.