In a closed system consisting of a cannon and a cannonball, the kinetic energy of a cannon is 72,000 J. If the cannonball is 18 kg and has a velocity of 23 m/s when fired from the cannon, what is the total kinetic energy of the system?(1 point) Responses 72,207 J 72,207 J 67,239 J 67,239 J 76,761 J 76,761 J 71,793 J
The total kinetic energy of the system can be calculated by adding the kinetic energy of the cannonball to the kinetic energy of the cannon.
The kinetic energy of the cannonball can be calculated using the formula:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass of the cannonball, and v is its velocity.
Plugging in the values given:
KE_cannonball = 1/2 * 18 kg * (23 m/s)^2
= 1/2 * 18 kg * 529 m^2/s^2
= 4,746 J
The kinetic energy of the cannon is given as 72,000 J.
Therefore, the total kinetic energy of the system is:
Total KE = KE_cannonball + KE_cannon
= 4,746 J + 72,000 J
= 76,746 J
So the closest answer is 76,761 J, which is the correct answer.