f(x)=x^2+1 when x : -2,-1,0,1,2
To find the corresponding values of f(x) for the given x-values, we substitute each x-value into the equation f(x) = x^2 + 1.
For x = -2:
f(-2) = (-2)^2 + 1
f(-2) = 4 + 1
f(-2) = 5
For x = -1:
f(-1) = (-1)^2 + 1
f(-1) = 1 + 1
f(-1) = 2
For x = 0:
f(0) = (0)^2 + 1
f(0) = 0 + 1
f(0) = 1
For x = 1:
f(1) = (1)^2 + 1
f(1) = 1 + 1
f(1) = 2
For x = 2:
f(2) = (2)^2 + 1
f(2) = 4 + 1
f(2) = 5
Therefore, f(x) for the given x-values is:
f(-2) = 5
f(-1) = 2
f(0) = 1
f(1) = 2
f(2) = 5