A train starts it's journey from Rawalpindi station to Lahore junction.it is moving with a constant acceleration of 10ms-2 .find it's velocity and distance travelled after 2hrs
To find the velocity and distance travelled, we need to use the equations of motion.
We have the following information:
Initial velocity (u) = 0 m/s (since the train starts from rest)
Acceleration (a) = 10 m/s^2
Time (t) = 2 hours = 2 * 60 * 60 = 7200 seconds
Using the equation: v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
We can substitute the given values into the equation:
v = 0 + (10 * 7200)
v = 0 + 72000
v = 72000 m/s
Therefore, the velocity of the train after 2 hours is 72000 m/s.
To find the distance travelled, we can use the equation:
s = ut + 0.5at^2
where s is the distance travelled.
Again, substituting the given values into the equation:
s = 0 * 7200 + 0.5 * 10 * (7200)^2
s = 0 + 0.5 * 10 * 51840000
s = 0 + 259200000
s = 259200000 meters
Therefore, the distance travelled by the train after 2 hours is 259200000 meters.