The mean Mark of a group of 10 boys is 58 the main lack of seven of them is 6 what is the mean Mark of the remaining three boys
Let's call the mean mark of the remaining three boys X.
To find X, we need to know the total sum of their marks.
We know that the mean mark of the 10 boys is 58, which means the sum of their marks is 58 * 10 = 580.
We also know that the mean lack (difference between their marks and 6) of the seven boys is 6. So, the sum of their marks is 6 * 7 = 42.
If we subtract the sum of the seven boys' marks from the total sum of marks, we can find the sum of the remaining three boys' marks: 580 - 42 = 538.
To find X (the mean mark of the remaining three boys), we divide the sum of their marks by 3 (since there are three boys): 538 / 3 = 179.33.
Therefore, the mean mark of the remaining three boys is approximately 179.33.