find f(a+4) when f(x)=x^2-5
To find f(a+4), we substitute a+4 for x in the function f(x) = x^2 - 5.
f(a+4) = (a+4)^2 - 5
Expanding the square gives us:
f(a+4) = (a^2 + 8a + 16) - 5
Simplifying further:
f(a+4) = a^2 + 8a + 16 - 5
f(a+4) = a^2 + 8a + 11
Therefore, f(a+4) = a^2 + 8a + 11.