It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reaction:
2 NaOH + H2CO3 → Na2CO3 + 2 H2O
The concentration of the carbonic acid is _____.
(1 point)
Responses
0.10 M
0.10 M
0.24 M
0.24 M
0.96 M
0.96 M
0.48 M
To find the concentration of the carbonic acid (H2CO3), we need to use the stoichiometry of the reaction.
From the reaction, we can see that 2 moles of NaOH react with 1 mole of H2CO3. Therefore, the number of moles of NaOH can be calculated by:
moles of NaOH = (volume of NaOH in L) x (concentration of NaOH in M)
moles of NaOH = 0.060 L x 0.20 M
moles of NaOH = 0.012 mol
Since there is a 1:1 stoichiometric ratio between NaOH and H2CO3, we know that the number of moles of H2CO3 is also 0.012 mol.
The concentration of the carbonic acid can be calculated using the formula:
concentration of H2CO3 = (moles of H2CO3) / (volume of H2CO3 in L)
concentration of H2CO3 = 0.012 mol / 0.025 L
concentration of H2CO3 = 0.48 M
Therefore, the concentration of the carbonic acid (H2CO3) is 0.48 M.