How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)? KE=12mv2 (1 point) Responses 266.5 J 266.5 J 1.3 J 1.3 J 35.9 J 35.9 J 151.2 J
To solve this problem, we can plug the given values into the kinetic energy equation KE=1/2mv^2.
For the first case, when the bowling ball is rolling at 16 mph (7.1 m/s):
KE₁ = 1/2 * 6 kg * (7.1 m/s)^2
KE₁ ≈ 151.2 J
For the second case, when the bowling ball is rolling at 14 mph (6.2 m/s):
KE₂ = 1/2 * 6 kg * (6.2 m/s)^2
KE₂ ≈ 119.1 J
The difference in kinetic energy is:
ΔKE = KE₁ - KE₂
ΔKE ≈ 151.2 J - 119.1 J
ΔKE ≈ 32.1 J
Therefore, the correct answer is 32.1 J.