Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point) Responses 855 N to the south and 759 N to the west 855 N to the south and 759 N to the west 795 N to the north and 855 N to the east 795 N to the north and 855 N to the east 855 N to the north and 795 N to the east 855 N to the north and 795 N to the east 795 N to the south and 855 N to the west
To find the net forces acting on the crate, we first need to find the individual components of the forces.
The north-south (vertical) forces are the sum of the forces pushing north and the forces pushing south:
Total north-south force = 960 N (north force) - 105 N (south force) = 855 N to the north.
The east-west (horizontal) forces are the sum of the forces pushing east and the forces pushing west:
Total east-west force = 875 N (east force) - 80 N (west force) = 795 N to the east.
So, the total net forces acting on the crate are 855 N to the north and 795 N to the east. Therefore, the correct response is:
795 N to the north and 855 N to the east.