A big rig truck loses its breaks going down a steep highway. The truck has a mass of 36,200 kilograms and is traveling at 78 miles per hour (34.8 meters per second). How much kinetic energy does the truck have when the driver turns into the deep gravel of an emergency ramp?%0D%0A%0D%0AKE=12mv2%0D%0A%0D%0A%0D%0A=%0D%0A1%0D%0A2%0D%0A%0D%0A%0D%0A2%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A629,880 J%0D%0A629,880 J%0D%0A%0D%0A43,839,648 J%0D%0A43,839,648 J%0D%0A%0D%0A110,120,400 J%0D%0A110,120,400 J%0D%0A%0D%0A21,919,824 J
To calculate the kinetic energy of the truck, we can use the formula:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity.
Plugging in the given values:
KE = 1/2 * 36200 kg * (34.8 m/s)^2
Simplifying:
KE = 0.5 * 36200 kg * 1210.4 m^2/s^2
KE = 43976080 J
Therefore, the kinetic energy of the truck when the driver turns into the deep gravel of an emergency ramp is 43,976,080 J.