Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)%0D%0AResponses%0D%0A%0D%0A855 N to the north and 795 N to the east%0D%0A855 N to the north and 795 N to the east%0D%0A%0D%0A795 N to the south and 855 N to the west%0D%0A795 N to the south and 855 N to the west%0D%0A%0D%0A855 N to the south and 759 N to the west%0D%0A855 N to the south and 759 N to the west%0D%0A%0D%0A795 N to the north and 855 N to the east
To find the total net forces acting on the crate, we need to consider the horizontal and vertical forces separately.
Horizontal forces:
- The worker pushing east exerts a force of 875 N to the east.
- The worker pushing north does not contribute to the horizontal forces since they are pushing perpendicular to the east-west direction.
- The friction between the crate and the floor is directed west with a force of 80 N.
The total horizontal net force is 875 N - 80 N = 795 N to the east.
Vertical forces:
- The worker pushing east does not contribute to the vertical forces since they are pushing perpendicular to the north-south direction.
- The worker pushing north exerts a force of 960 N to the north.
- The friction between the crate and the floor is directed south with a force of 105 N.
The total vertical net force is 960 N - 105 N = 855 N to the north.
Therefore, the total north-south net force is 855 N to the north and the total east-west net force is 795 N to the east.