A mixture of nitrogen and argon gas is compressed from a volume of 70.0 L to a volume of 61.0 L, while the pressure is held constant at 14.0 atm. Calculate the work done on the gas mixture.
22 kJ
13 kJ
-13 kJ
-22 k
To calculate the work done on a gas mixture, we can use the formula:
Work = -PΔV
Where:
- Work is the work done on the gas mixture (in joules, J)
- P is the constant pressure (in atmospheres, atm)
- ΔV is the change in volume (in liters, L)
In this case, the pressure is constant at 14.0 atm, and the change in volume is from 70.0 L to 61.0 L.
Using the formula, we can calculate the work done:
Work = -14.0 atm * (61.0 L - 70.0 L)
Work = -14.0 atm * (-9.0 L)
Work = 126.0 atm*L
Since the units of atm*L are not in joules, we need to convert them. 1 atm*L = 101.325 J
Work = 126.0 atm*L * 101.325 J/atm*L
Work ≈ 12773.65 J
Rounded to the nearest kilojoule, the work done on the gas mixture is approximately 13 kJ.
Therefore, the correct answer is 13 kJ.