Using the quadratic formula, find the solutions to
X^2-16x-15=0
To find the solutions using the quadratic formula, first identify the values of a, b, and c in the equation: X^2-16x-15=0.
In this equation, a=1, b=-16, and c=-15.
Using the quadratic formula, X = (-b ± √(b^2 - 4ac)) / (2a), we can substitute in the values:
X = (-(-16) ± √((-16)^2 - 4(1)(-15))) / (2(1))
Simplifying:
X = (16 ± √(256 + 60)) / 2
X = (16 ± √(316)) / 2
X = (16 ± √(4 * 79)) / 2
X = (16 ± 2√79) / 2
X = 8 ± √79
Therefore, the solutions to the equation X^2-16x-15=0 are X = 8 + √79 and X = 8 - √79.