A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24 atm. What is the partial pressure of hydrogen?
Use StartFraction P subscript a over P subscript T EndFraction equals StartFraction n subscript a over n subscript T EndFraction..
0.31 atm
0.93 atm
5.2 atm
31 atm
To find the partial pressure of hydrogen gas, we can use the formula
P(a) = (n(a) / n(T)) * P(T),
where P(a) is the partial pressure of hydrogen gas, n(a) is the number of moles of hydrogen gas, n(T) is the total number of moles in the container, and P(T) is the total pressure.
First, let's calculate the number of moles of hydrogen gas:
n(a) = 25% * 6.4 moles = 0.25 * 6.4 moles = 1.6 moles
Next, we can substitute the given values into the formula to find the partial pressure:
P(a) = (1.6 moles / 6.4 moles) * 1.24 atm
P(a) = 0.25 * 1.24 atm
P(a) = 0.31 atm
Therefore, the partial pressure of hydrogen gas is 0.31 atm.