A cardboard box weighing 90. N is pushed across a hardwood floor. The coefficient of kinetic friction for cardboard on wood is o
0.30. What is the minimum force that must be applied to keep the box moving ? Show work
The minimum force that must be applied to keep the box moving can be found using the equation:
force of friction = coefficient of friction * normal force
where the normal force is equal to the weight of the box. Given that the box weighing 90 N, the normal force is also 90 N.
force of friction = 0.30 * 90 N
force of friction = 27 N
Therefore, the minimum force that must be applied to keep the box moving is 27 N.