Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
Responses
855 N to the north and 795 N to the east
855 N to the north and 795 N to the east
795 N to the north and 855 N to the east
795 N to the north and 855 N to the east
855 N to the south and 759 N to the west
855 N to the south and 759 N to the west
795 N to the south and 855 N to the west
To find the net force in the north-south direction, we need to subtract the force due to friction in the south direction from the force exerted in the north direction.
Total net force in the north-south direction = Force exerted in the north direction - Force due to friction in the south direction
= 960 N - 105 N
= 855 N
To find the net force in the east-west direction, we need to subtract the force due to friction in the west direction from the force exerted in the east direction.
Total net force in the east-west direction = Force exerted in the east direction - Force due to friction in the west direction
= 875 N - 80 N
= 795 N
Therefore, the correct answer is:
855 N to the north and 795 N to the east.