3+4j÷-3-j

To simplify the expression 3+4j÷-3-j, we can rewrite it as follows:

3 + 4j ÷ (-3 - j)

To divide complex numbers, we multiply the numerator and denominator by the conjugate of the denominator:

= (3 + 4j) × (-3 + j) ÷ ((-3 - j) × (-3 + j))

Using the distributive property, we can multiply the numerators:

= (-9 - 3j + 12j - 4j^2) ÷ (-3^2 - j^2)

Since j^2 is equal to -1, the expression simplifies to:

= (-9 + 9j) ÷ (9 + 1)

= (-9 + 9j) ÷ 10

= -0.9 + 0.9j

Therefore, 3 + 4j ÷ -3 - j simplifies to -0.9 + 0.9j.