Two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. If the force between the spheres is 4,550 N and the charge on one object is 9.9×10-S c, what is the charge on the other object?
The force between two charged objects is given by Coulomb's Law:
F = k * (q1 * q2) / r^2
Where:
F is the force between the objects,
k is the electrostatic constant (approximately 9 × 10^9 N m^2/C^2),
q1 and q2 are the charges on the objects, and
r is the distance between the objects.
In this case, we are given:
F = 4,550 N,
q1 = 9.9 × 10^-5 C, and
r = 0.22 m.
We can rearrange the formula to solve for q2:
q2 = (F * r^2) / (k * q1)
Substituting the given values:
q2 = (4,550 N * (0.22 m)^2) / (9 × 10^9 N m^2/C^2 * 9.9 × 10^-5 C)
= (4,550 N * 0.0484 m^2) / (8.91 × 10^4 N m^2/C)
≈ 24.86 × 10^-5 C
≈ 2.486 × 10^-4 C
Therefore, the charge on the other object is approximately 2.486 × 10^-4 C.