Determine the period of the function f(x)=2sin(3x+π/3)+5 .(1 point) Responses 2π 2 pi π pi π9 Start Fraction pi over 9 End Fraction 2π3
The period of a sine function is given by the formula: T = 2π/wavelength, where the wavelength is the coefficient in front of x.
In this case, the coefficient in front of x is 3.
So, the period of the function f(x) = 2sin(3x+π/3)+5 is T = 2π/3.
Hence, the correct response is: π3.