Find the lengths of the sides of a triangle with vertices: (0, 0), (5, 0), (5, 12).
Using the distance formula:
The length of the side between (0, 0) and (5, 0) is $\sqrt{(5-0)^2 + (0-0)^2} = \sqrt{5^2 + 0^2} = \boxed{5}$.
The length of the side between (0, 0) and (5, 12) is $\sqrt{(5-0)^2 + (12-0)^2} = \sqrt{5^2 + 12^2} = \sqrt{25+144} = \sqrt{169} = \boxed{13}$.
The length of the side between (5, 0) and (5, 12) is $\sqrt{(5-5)^2 + (12-0)^2} = \sqrt{0^2 + 12^2} = \boxed{12}$.
5,12,12
5,5,12
5,12,5
5,12,13