A gas occupies a volume of 4.80 L at a temperature of 500 K. Find its volume at when the temperature becomes 250 K.
To solve this problem, we can use the combined gas law formula:
(P1 × V1) / T1 = (P2 × V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (same as initial pressure since it is not given)
V2 = final volume (unknown)
T2 = final temperature
Since the pressure (P2) remains constant, we can eliminate it from the equation. Therefore, the formula becomes:
(V1 / T1) = (V2 / T2)
Plugging in the given values:
V1 = 4.80 L
T1 = 500 K
T2 = 250 K
(4.80 L / 500 K) = (V2 / 250 K)
Cross-multiplying:
(4.80 L) × (250 K) = (500 K) × (V2)
1200 L*K = 500 K * V2
Dividing both sides by 500 K:
V2 = (1200 L*K) / (500 K)
V2 ≈ 2.4 L
Therefore, the volume of the gas at a temperature of 250 K is approximately 2.4 L.
a
9.60 L
b
1.25 L
c
2.40 L
d
10.2 L