Which of the equations above correctly demonstrate the law of conservation of matter? (Hint: to demonstrate the law of conservation of matter, the equation must have equal numbers of each type of atom on both sides of the arrow- it must be balanced.)
The equation A. 2H2O -> 2H2 + O2 correctly demonstrates the law of conservation of matter because it has equal numbers of hydrogen and oxygen atoms on both sides of the arrow.
a
Equation 1
b
Equation 2
c
Equation 3
d
Equation 4
To determine which equation correctly demonstrates the law of conservation of matter, we need to evaluate each equation and check if they have the same number of atoms on both sides of the arrow.
a. Equation 1: 2H2O -> 2H2 + O2
This equation correctly demonstrates the law of conservation of matter because there are 4 hydrogen atoms and 2 oxygen atoms on both sides of the arrow.
b. Equation 2: Na + Cl2 -> NaCl
This equation does not demonstrate the law of conservation of matter because there is 1 sodium atom and 2 chlorine atoms on the left side, but only 1 sodium atom and 1 chlorine atom on the right side.
c. Equation 3: C6H12O6 -> 2C2H5OH + 2CO2
This equation does not demonstrate the law of conservation of matter because there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms on the left side, but only 4 carbon atoms, 10 hydrogen atoms, and 4 oxygen atoms on the right side.
d. Equation 4: N2 + 3H2 -> 2NH3
This equation correctly demonstrates the law of conservation of matter because there are 2 nitrogen atoms and 6 hydrogen atoms on both sides of the arrow.
Therefore, the correct equations that demonstrate the law of conservation of matter are a. Equation 1 and d. Equation 4.