A team of students builds a lever as a science project. They expend 10,300 Joules of energy to lift some bricks with the lever.
If 6,283 Joules of energy are applied to the bricks, what is the lever's efficiency? (1 point)
To find the efficiency of the lever, we need to divide the useful output energy (the work done by the lever) by the input energy.
The useful output energy (work done by the lever) is given as 6,283 Joules.
The input energy is given as 10,300 Joules.
Therefore, the efficiency of the lever is:
Efficiency = (Useful output energy / Input energy) * 100
= (6,283 / 10,300) * 100
= 0.6103 * 100
= 61.03%
Therefore, the lever's efficiency is 61.03%.