For which value(s) of x does the function f(x)=(x2−4)23 have an absolute minimum? (1 point) Responses x = 0 x = 0 x=−2 and x = 2 x = − 2 and x = 2 x=16−−√3 x = 16 3 x=−16−−√3 and x=16−−√3 x = − 16 3 and x = 16 3 The function does not have an absolute minimum.
The function $f(x) = \left(\dfrac{x^2-4}{3}\right)^2$ is a quadratic function that is always non-negative. This is because we are squaring the expression $\dfrac{x^2-4}{3}$, which is a real number for all values of $x$. Therefore, the function does not have an absolute minimum. So the correct answer is:
$\boxed{\text{The function does not have an absolute minimum.}}$