Express (x-11)^2 as a trinomial in standard form
(x-11)^2 can be expanded as (x-11)(x-11) using the distributive property.
Expanding this expression gives:
(x-11)(x-11) = x(x) + x(-11) + (-11)(x) + (-11)(-11)
= x^2 - 11x - 11x + 121
= x^2 - 22x + 121
Therefore, (x-11)^2 expressed as a trinomial in standard form is x^2 - 22x + 121.