John spent 2/3 of his money on a pen and a calculator. Calculator cost 3 times as much as the pen. If calculator cost 24 dollars how much money did he have left
Let's assume John's total money was "x" dollars.
If John spent 2/3 of his money, then he has 1/3 of his money left.
Let the cost of the pen be "p" dollars.
Since the calculator cost 3 times as much as the pen, the cost of the pen is 1/3 * 24 dollars = <<1/3*24=8>>8 dollars.
If we assume the cost of the pen as "p" dollars, then the cost of the calculator is 3 * p = 24 dollars.
Therefore, p = 24/3 = <<24/3=8>>8 dollars.
The total cost of the pen and the calculator is 8 + 24 = <<8+24=32>>32 dollars.
Therefore, the money John has left is x - 32 dollars.
Since John has 1/3 of his money left, we have (1/3)* x = x - 32 dollars.
Multiplying both sides of the equation by 3 gives us x = 3(x - 32).
Expanding the right side of the equation gives us x = 3x - 96.
Subtracting "3x" from both sides gives us -2x = -96.
Dividing both sides by -2 gives us x = 48 dollars.
Therefore, John has 48 - 32 = <<48-32=16>>16 dollars left. Answer: \boxed{16}.