Every year in Delaware, there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. The equation y=−16x2+105x+12
can be used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the pumpkin has been in the air. What is the maximum height that the pumpkin reaches? How many seconds have passed when the pumpkin hits the ground? (Hint: If the pumpkin hits the ground, its height is 0 feet.)(1 point)
Responses
The pumpkin's maximum height is 3.28 feet, and it hits the ground after 6.67 seconds.
The pumpkin's maximum height is 3.28 feet, and it hits the ground after 6.67 seconds.
The pumpkin's maximum height is 3.28 feet, and it hits the ground after 184.27 seconds.
The pumpkin's maximum height is 3.28 feet, and it hits the ground after 184.27 seconds.
The pumpkin's maximum height is 184.27 feet, and it hits the ground after 6.67 seconds.
The pumpkin's maximum height is 184.27 feet, and it hits the ground after 6.67 seconds.
The pumpkin's maximum height is 184.27 feet, and it hits the ground after 3.28 seconds.
The correct answer is:
The pumpkin's maximum height is 3.28 feet, and it hits the ground after 6.67 seconds.