Write an equation in slope intercept form for a line that passes through the origin with a slope of 3/2
The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
Since the line passes through the origin (0,0), the y-intercept is 0. Therefore, b = 0.
The slope is given as 3/2. Therefore, m = 3/2.
Substituting the values of m and b into the slope-intercept form, the equation becomes: y = (3/2)x + 0
Simplifying the equation, the final answer is: y = (3/2)x
3y = 2x
2y = 3x
y = 3/2x
3x - 2y = 0
My apologies for the mistakes in my previous response. Let's correct them.
Given that the line passes through the origin (0,0) and has a slope of 3/2, we can write the equation in slope-intercept form as:
y = mx + b
Since the line passes through the origin (0,0), the y-intercept (b) is 0.
The slope (m) is given as 3/2.
Substituting the values of m and b into the slope-intercept form, the equation becomes:
y = (3/2)x + 0
Simplifying the equation, the final answer is:
y = (3/2)x