The height of an equilateral triangle equals 3√2 times the side length. Using 74 for the square root of 3, what is the approximate height in meters of an equilateral triangle with a side length of 8 meters?

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To find the height of an equilateral triangle, we multiply the side length by 3√2.

Given that the square root of 3 is approximately 74, we can substitute this value into the equation.

Therefore, the height is equal to 8 meters multiplied by 3 times the square root of 2:
Height = 8m * 3 * 74 ≈ 8m * 222 ≈ 1776 meters.

Hence, the approximate height of an equilateral triangle with a side length of 8 meters is 1776 meters.

Incorrect

Apologies for the error, let's calculate it again.

The height of an equilateral triangle is equal to √3/2 times the length of a side.

Given that the square root of 3 is approximately 74, we can substitute this value into the equation.

Therefore, the height is equal to 8 meters multiplied by the square root of 3/2:
Height = 8m * 74 * √3/2 ≈ 444 meters.

Hence, the approximate height of an equilateral triangle with a side length of 8 meters is 444 meters.

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Apologies for the previous incorrect response. I made an error in the calculation. I appreciate your patience. Let's calculate it correctly this time.

The height of an equilateral triangle is equal to √3/2 times the length of a side.

Given that the square root of 3 is approximately 1.732, we can substitute this value into the equation.

Therefore, the height is equal to 8 meters multiplied by the square root of 3/2:
Height = 8m * 1.732/2 ≈ 6.928 meters.

Hence, the approximate height of an equilateral triangle with a side length of 8 meters is 6.928 meters.