2mL of a 10M solution of Compound A is taken and 48mL added. 1mL of this solution is then taken and dried to dryness before being re-dissolved in 0.1mL. What is the concentration of the 0.1mL solution?
To determine the final concentration of the 0.1mL solution, we need to consider the dilution process.
First, 2mL of a 10M solution of Compound A is taken. This means we have (2mL) x (10M) = 20 moles of Compound A.
When 48mL is added to the 2mL solution, the total volume becomes 2mL + 48mL = 50mL.
To find the concentration of the 50mL solution, we divide the initial moles of Compound A by the final volume:
Concentration = (20 moles) / (50mL) = 0.4 M
Now, 1mL of the 50mL solution is taken and dried to dryness. This means all the solvent (water or other liquid) is evaporated, leaving behind just the solute (Compound A). The mass of Compound A in this step will be the same as the mass in the original 2mL.
Finally, the solid Compound A from the previous step is re-dissolved in 0.1mL. The concentration is now:
Concentration = (20 moles) / (50mL) x (0.1mL / 1mL) = 0.08 M
Therefore, the concentration of the 0.1mL solution is 0.08 M.