A rectangular large fish tank was filled with water to a height of 8 cm. Its rectangular base was 40 cm by 25 cm wide. When 14 liters of water were poured into the fish tank, the water level rose to 0.8 of the height of fish tank. What was the height of the tank
The volume of the tank can be calculated by multiplying the base area by the height: 40 cm * 25 cm * 8 cm = <<40*25*8=8000>>8000 cm^3.
Since 1 liter is equal to 1000 cm^3, the volume of 14 liters is 14 * 1000 = <<14*1000=14000>>14000 cm^3.
The new volume of the tank after adding 14 liters of water is 8000 cm^3 + 14000 cm^3 = <<8000+14000=22000>>22000 cm^3.
Let's denote the height of the tank as h cm.
It is given that the new water level is 0.8 times the height of the tank, so the new water level is 0.8 * h = 0.8h cm.
The new volume of the tank is equal to the base area multiplied by the new height of the water level: 40 cm * 25 cm * 0.8h cm = 200h cm^3.
Equating the two volumes, we get 200h cm^3 = 22000 cm^3.
Dividing both sides of the equation by 200 cm^3, we get h = 22000 cm^3 / 200 cm^3.
The height of the tank is h = <<22000/200=110>>110 cm. Answer: \boxed{110}.