What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)?
(1 point)
Responses
y = 3x + 1
y = x – 3
y = 2x + 5
y = 2x – 5
To find the equation in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
The formula to find the slope (m) is:
m = (y2 - y1) / (x2 - x1)
Using the given points (1, –3) and (3, 1), we can substitute the values into the formula:
m = (1 - (-3)) / (3 - 1)
m = 4 / 2
m = 2
Now, we have the value of the slope (m), and we need to find the y-intercept (b). We can choose any of the given points to substitute into the equation y = mx + b. Let's use the point (1, -3):
-3 = (2)(1) + b
-3 = 2 + b
b = -5
Therefore, the equation for the line that passes through the points (1, –3) and (3, 1) in slope-intercept form is:
y = 2x - 5