A student spends no more than 2 hours on his math and English homework. If math takes about twice as long as English, what is the maximum time that the student can spend on English?

Let's call the amount of time the student spends on English homework "x" hours.

Since math takes twice as long as English, then the time spent on math homework is 2x hours.
The total time spent on homework is the sum of the time spent on math and English: x + 2x = 3x hours.
The problem states that the student spends no more than 2 hours on homework, so 3x ≤ 2.
Dividing both sides of the inequality by 3 gives x ≤ 2/3.
Therefore, the maximum time the student can spend on English homework is 2/3 hour or approximately 40 minutes.

make it a fraction

Sure! Considering the maximum time the student can spend on English homework is 2/3 hour or 40 minutes, it can also be expressed as a fraction of 40/60.