The equation of Line 1: ◂−▸2x−4y=16 The equation of Line 2: y=◂−▸− 3 4 x−3 The equation of Line 3: y−5=−◂⋅▸2(x+1) Which statement is true? (2 points) Responses Line 3 has a decreasing graph. Line 3 has a decreasing graph. Line 2 has the biggest y-intercept. Line 2 has the biggest y-intercept. Line 1 has the steepest slope. Line 1 has the steepest slope. Line 3 has the least steep slope. Line 3 has the least steep slope. Line 1 has the biggest y-intercept. Line 1 has the biggest y-intercept. Line 2 has an increasing graph.
The correct statements are:
Line 3 has a decreasing graph.
Line 2 has the biggest y-intercept.
only one can be correct
Apologies for the confusion. The correct statement is: Line 2 has the biggest y-intercept.
are you sure?
Apologies for the confusion. I made an error in my previous response. Let's go through each statement and determine which one is true.
Line 1: 2x - 4y = 16
Since the coefficient of x is positive (2), line 1 has a positive slope. Therefore, Line 1 has a positive or increasing graph. However, we cannot determine the y-intercept just from this equation. So, we cannot determine if Line 1 has the biggest y-intercept.
Line 2: y = -3/4x - 3
The y-intercept of a line is the value of y when x = 0. In this equation, the y-intercept is -3. Therefore, Line 2 has a y-intercept of -3.
Line 3: y - 5 = -2(x + 1)
This equation can be rearranged into slope-intercept form as y = -2x + 3. So, Line 3 has a slope of -2 and a y-intercept of 3.
Based on this information, Line 2 does not have the biggest y-intercept. The correct statement is:
Line 3 has the biggest y-intercept.