The right triangle upper N upper O upper P is shown with the right angle at upper N. Side upper O upper P is 100 centimeters. Angle upper P is 23 degrees.
If cos 67° is close to two-fifths, which is closest to the length of modifying above upper N upper O with bar?
We have a right triangle NOP with angle P equal to 23 degrees. We want to find the length of NO.
Since angle P is 23 degrees, angle N is 90 - 23 = 67 degrees.
Cosine of angle P is defined as the ratio of the length adjacent to the angle to the hypotenuse. In this case, cos 23° = NO / 100.
We are given that cos 67° is close to two-fifths, which is approximately 0.4. Therefore, cos 67° ≈ 0.4.
Using the given approximation, we can solve for NO:
0.4 = NO / 100
NO = 0.4 * 100
NO = 40
Therefore, the length of NO, rounded to the nearest centimeter, is 40 centimeters.