Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
1 855 N to the south and 759 N to the west
2 795 N to the north and 855 N to the east
3 855 N to the north and 795 N to the east
4 795 N to the south and 855 N to the west
To find the total net force in the north-south direction, we need to subtract the southward force from the northward force. The northward force is 960 N and the southward force is 105 N (friction). So, the total north-south net force is 960 N - 105 N = 855 N to the north.
To find the total net force in the east-west direction, we need to subtract the westward force from the eastward force. The eastward force is 875 N and the westward force is 80 N (friction). So, the total east-west net force is 875 N - 80 N = 795 N to the east.
Therefore, the correct answer is 3) 855 N to the north and 795 N to the east.