Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
Responses
795 N to the north and 855 N to the east
795 N to the north and 855 N to the east
855 N to the south and 759 N to the west
855 N to the south and 759 N to the west
855 N to the north and 795 N to the east
855 N to the north and 795 N to the east
795 N to the south and 855 N to the west
To find the net north-south force, we subtract the force of friction in the south direction from the north force applied by the worker pushing:
Total north-south net force = 960 N - 105 N = 855 N to the north.
To find the net east-west force, we subtract the force of friction in the west direction from the east force applied by the worker pushing:
Total east-west net force = 875 N - 80 N = 795 N to the east.
Therefore, the correct answer is:
855 N to the north and 795 N to the east.