what is the surface area of a square pyramid where the base Edge is 8 ft in the slant height is 16 ft

128 ft
320 ft
512 ft
256 ft

if any of the questions i give you dont have a "correct" answer, then find the closer one

To find the surface area of a square pyramid, we need to calculate the sum of the areas of the base and the four triangular faces.

Given that the base edge is 8 ft, the area of the base of the pyramid can be calculated as the square of the edge length:

Base area = (8 ft)^2 = 64 ft^2

The slant height is given as 16 ft, and since the pyramid is a square pyramid, all four triangular faces will have the same base (equal to the base edge) and height (equal to the slant height).

The area of each triangular face can be calculated as:

Face area = (1/2) × (base) × (height)
Face area = (1/2) × (8 ft) × (16 ft) = 64 ft^2

The surface area of the pyramid is the sum of the base area and the four triangular face areas:

Surface area = Base area + 4 × Face area
Surface area = 64 ft^2 + 4 × 64 ft^2
Surface area = 64 ft^2 + 256 ft^2
Surface area = 320 ft^2

Therefore, the surface area of the square pyramid is 320 ft^2. From the options provided, the closest answer is 320 ft^2.