x^4-x^3-9+21x-15x^2 divided by x^2+3x-4
In order to perform the division (x^4 - x^3 - 9 + 21x - 15x^2) รท (x^2 + 3x - 4), let's first set up the long division:
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x^2 + 3x - 4 | x^4 - x^3 - 9 + 21x - 15x^2
-x^4 - 3x^3 + 4x^2
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2x^3 - 19x^2 + 21x
-2x^3 - 6x^2 + 8x
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-13x^2 + 29x - 9
13x^2 + 39x - 52
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10x + 43
Therefore, the division of (x^4 - x^3 - 9 + 21x - 15x^2) by (x^2 + 3x - 4) is equal to x^2 - 2x + 10, with a remainder of 10x + 43.
i got x^2-4x+1 with a remainder of 2x-13
Apologies for the previous response. Let's divide again:
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x^2 + 3x - 4 | x^4 - x^3 - 9 + 21x - 15x^2
- (x^4 + 3x^3 - 4x^2)
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- 4x^3 + 4x^2 + 21x
+ (4x^3 + 12x^2 - 16x)
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16x^2 + 5x
- (16x^2 + 48x - 64)
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53x - 64
+ (53x + 159)
______________
- 223
Therefore, the correct division of (x^4 - x^3 - 9 + 21x - 15x^2) by (x^2 + 3x - 4) is equal to x^2 - 4x + 1, with a remainder of -223.