Bob heads out into a lake at an angle of 47 degrees with respect to the shore. If his boat is capable of a speed of 2.9 m/s how far from the land will he be in 3 min. and 24 sec.? Answer in units of m.
his movement relative to the shore is 2.9*sin49 m/s
distance= relative velocity*time
be certain to change time to seconds.
I am confused about where the 49 came from... is it supposed to be 47 ?
yes, 47
Thanks!
To find the distance from the land where Bob will be, we need to calculate the horizontal displacement after 3 minutes and 24 seconds. Let's break down the problem into steps:
Step 1: Convert the time to seconds.
3 minutes and 24 seconds can be converted to a single unit of time, which is seconds.
3 minutes = 3 * 60 seconds = 180 seconds.
Therefore, 3 minutes and 24 seconds = 180 seconds + 24 seconds = 204 seconds.
Step 2: Calculate the horizontal displacement.
The horizontal component of Bob's velocity can be found by multiplying his boat's speed (2.9 m/s) by the cosine of the angle he heads out, 47 degrees.
Horizontal velocity = 2.9 m/s * cos(47 degrees).
Step 3: Calculate the distance from the land.
The distance traveled by Bob can be obtained by multiplying the horizontal velocity with the time.
Distance = Horizontal velocity * Time = (2.9 m/s * cos(47 degrees)) * 204 seconds.
Finally, we can calculate the value using the given formula.