A carry-on suitcase is 9.5 inches long, 16 inches wide, and 22.5 inches high. What is the surface area of the suitcase?(Math question)
a. 725.75 in.^2
b. 96 in.^2
c. 3,420 in.^2
d. 1,451.5 in.^2
The surface area of the suitcase is equal to the sum of the areas of its six sides.
Area of one side = length * width
Area of one side = 9.5 inches * 16 inches = 152 square inches
Area of another side = length * width
Area of another side = 9.5 inches * 16 inches = 152 square inches
Area of one more side = length * height
Area of one more side = 9.5 inches * 22.5 inches = 213.75 square inches
Area of one more side = length * height
Area of one more side = 9.5 inches * 22.5 inches = 213.75 square inches
Area of one more side = width * height
Area of one more side = 16 inches * 22.5 inches = 360 square inches
Area of one more side = width * height
Area of one more side = 16 inches * 22.5 inches = 360 square inches
Total surface area = 152 square inches + 152 square inches + 213.75 square inches + 213.75 square inches + 360 square inches + 360 square inches = 1451.5 square inches
Therefore, the surface area of the suitcase is 1451.5 in.^2 (option d).