Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise
1.(−2,−4)
2.(4,−2)
3.(−4, 2)
4.(−4,−2)
To rotate a point 270 degrees counterclockwise, we can use the following formula:
x' = -y
y' = x
Applying this formula to point A (2, 4), we get:
x' = -4
y' = 2
Therefore, the new point after rotating 270 degrees counterclockwise is (−4, 2).
So, the correct answer is 3.(−4, 2).