solve the equation to find the value of x show all your work
log2(3x+5)=5
To solve the equation log2(3x+5) = 5, we need to isolate the variable x.
First, we can rewrite the equation using exponentiation:
2^(log2(3x + 5)) = 2^5
By the logarithm property, the base (2) and the exponent (log2(3x + 5)) cancel out, leaving us with:
3x + 5 = 32
Next, we'll subtract 5 from both sides of the equation to isolate 3x:
3x = 32 - 5 = 27
Finally, we divide both sides of the equation by 3 to solve for x:
x = 27 / 3 = 9
Therefore, the value of x is 9.