The length of a rectangle is 5in longer than its width.
If the perimeter of the rectangle is 38in , find its area.
Let's say the width of the rectangle is x inches.
Then, the length of the rectangle is (x + 5) inches.
The perimeter of a rectangle is given by 2(length + width).
So, in this case, the perimeter is 2(x + 5 + x) = 38 inches.
Simplifying this equation, we get 2(2x + 5) = 38.
Multiplying through the brackets, we get 4x + 10 = 38.
Subtracting 10 from both sides, we get 4x = 28.
Dividing by 4, we get x = 7.
So, the width of the rectangle is 7 inches and the length is 7 + 5 = 12 inches.
The area of a rectangle is given by length multiplied by width.
Hence, the area of this rectangle is 7 * 12 = 84 square inches. Answer: \boxed{84}.