Find the period and amplitude of the following function. Then sketch the function from 0 to 2π.
y = -3 sin 2π0
show your work
To find the period and amplitude of the function y = -3 sin 2π0, we can first identify the form of the function as y = A sin (Bx - C) + D.
In this case, A = -3 since the coefficient in front of sin is -3. B = 2π since the coefficient in front of x is 2π. C = 0 since there is no phase shift. D = 0 since there is no vertical shift.
The amplitude of the function is given by |A|, so the amplitude is 3.
The period of the function is given by 2π/|B|, so the period is (2π)/(2π) = 1.
To sketch the function from 0 to 2π, we can use the general shape of a sine function: it starts at the origin and oscillates between 1 and -1 with a period of 2π.
Since the amplitude in this case is 3, the function will oscillate between 3 and -3.
Using this information, we can sketch the graph.