A common trait found in orange tabby cats is the following: being awesome (A) is dominant to being average (a).
A male cat that is homozygous dominant for the A trait is mated with a female cat that is homozygous recessive.
For a cross with four offspring, what is the probability that they will have an offspring who is heterozygous?
____ out of ____
To determine the probability of having offspring who are heterozygous, we need to analyze the genotypes of both parents and then use a Punnett square to determine the possible genotypes of the offspring.
Given:
Male cat (homozygous dominant for the A trait): AA
Female cat (homozygous recessive): aa
Using a Punnett square, we can determine the possible genotypes of the offspring:
| A | A
---------------------
a | Aa | Aa
a | Aa | Aa
Out of the four possible offspring, there are 4 heterozygous offspring (Aa) and 0 offspring that are either homozygous dominant (AA) or homozygous recessive (aa).
Therefore, the probability of having an offspring who is heterozygous is 4 out of 4 or 100%.