Find the first four terms of the sequence given by the following.
^an=2(4)^n-1, n=1,2,3
To find the first four terms of the sequence, we plug in the values of n=1, 2, 3 into the formula ^an = 2(4)^n-1.
When n=1, ^a1 = 2(4)^1-1 = 2(4)^0 = 2(1) = 2.
When n=2, ^a2 = 2(4)^2-1 = 2(4)^1 = 2(4) = 8.
When n=3, ^a3 = 2(4)^3-1 = 2(4)^2 = 2(16) = 32.
Therefore, the first four terms of the sequence are 2, 8, 32.