Determine whether the following individual events are independent or dependent. Then find the probability of the combined event.
Randomly drawing and immediately eating two red pieces of candy in a row from a bag that contains 10 red pieces of candy out of 44 pieces of candy total.
The events of drawing and eating the red pieces of candy are dependent because the number of red pieces of candy decrease after each draw and eat.
To find the probability of the combined event, we can multiply the probabilities of each individual event.
The probability of drawing and eating the first red candy is $\frac{10}{44}$.
After eating the first candy, there are now 43 total candies in the bag and 9 red candies remaining. The probability of drawing and eating the second red candy is $\frac{9}{43}$.
Therefore, the probability of drawing and immediately eating two red pieces of candy in a row is $\frac{10}{44} \times \frac{9}{43} = \frac{90}{1892}$.