Tickets to the baseball game are on sale for $1.50 off the regular price. Dea buys 6 tickets. If her total cost is $51, what is the regular price of each ticket? Write and solve an equation of the form p(x±q)=r . Then write a sentence to explain your answer like a 7th grader
Let's represent the regular price of each ticket as p.
According to the problem, the tickets are on sale for $1.50 off the regular price. Therefore, the discounted price of each ticket is p - $1.50.
Dea buys 6 tickets, so her total cost is 6 * (p - $1.50), which is equal to $51.
Writing an equation using the given information:
6(p - $1.50) = $51
To solve this equation, we can distribute 6:
6p - $9 = $51
Now, let's isolate p by moving the constant term to the other side:
6p = $51 + $9
6p = $60
Finally, to find the regular price of each ticket, we divide both sides of the equation by 6:
p = $60 / 6
p = $10
So, the regular price of each ticket is $10.
Explanation: Tickets to the baseball game were on sale for $1.50 off the regular price. Dea bought 6 tickets for a total cost of $51. To find the regular price of each ticket, I wrote and solved an equation. I found that the regular price of each ticket is $10.
write an equation for it
The equation for determining the regular price of each ticket would be: 6(p - $1.50) = $51
could you explain how you solve it in 7th grade terms
Sure, I'd be happy to explain it in simpler terms!
First, let's represent the regular price of each ticket as p.
The problem tells us that the tickets are on sale for $1.50 off the regular price. So, the discounted price of each ticket is p - $1.50.
Next, we know that Dea buys 6 tickets. To find her total cost, we multiply the number of tickets, which is 6, by the discounted price of each ticket, which is p - $1.50. This gives us 6 times (p - $1.50).
According to the problem, Dea's total cost is $51. So, we can set up an equation: 6(p - $1.50) = $51. This equation represents that 6 times the discounted price of each ticket is equal to $51.
To solve this equation, we can simplify it. Multiplying 6 with p and 6 with -$1.50 gives us 6p - $9 = $51.
Next, we want to isolate the variable p, which represents the regular price of each ticket. So, we bring -$9 to the other side of the equation by adding $9 to both sides. This gives us 6p = $51 + $9, which simplifies to 6p = $60.
Finally, to find the regular price of each ticket, we divide both sides of the equation by 6. This gives us p = $10.
Therefore, the regular price of each ticket is $10.
where did u get nine
I apologize for the confusion. The equation should be 6(p - $1.50) = $51.
To solve this equation, we need to distribute the 6 to both terms inside the parentheses. This gives us 6p - 6($1.50) = $51.
Next, we need to simplify the expression by multiplying 6 with $1.50. $1.50 times 6 is $9.
The equation now becomes 6p - $9 = $51.
To solve for p, we need to isolate the variable p by moving the constant term ($9) to the other side of the equation. We can do this by adding $9 to both sides:
6p - $9 + $9 = $51 + $9
6p = $60
To find the regular price of each ticket, we need to solve for p. We do this by dividing both sides of the equation by 6:
6p/6 = $60/6
p = $10
So, the regular price of each ticket is $10.