Surface Area of Pyramids Quick Check
Find the surface area of a rectangular pyramid with these measurements: l = 8yd , w = 4yd and h = 2yd (1 por
72.52y * d ^ 2
O 55.55y * d ^ 2
O 66y * d ^ 2
43.31yd .^ 2
To find the surface area of a rectangular pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base (rectangle) is calculated by multiplying the length (8yd) by the width (4yd):
Area of the base = 8yd * 4yd = 32yd^2
Now, let's calculate the area of the triangular faces. Each triangular face has a base equal to the length of the rectangle (8yd) and a height equal to the height of the pyramid (2yd). Therefore, the area of each triangular face is:
Area of each triangular face = (1/2) * base * height = (1/2) * 8yd * 2yd = 8yd^2
Since there are four triangular faces, the total area of the triangular faces is:
Total area of the triangular faces = 4 * 8yd^2 = 32yd^2
Finally, to find the surface area, we add the area of the base and the area of the four triangular faces:
Surface area = Area of the base + Total area of the triangular faces
Surface area = 32yd^2 + 32yd^2
Surface area = 64yd^2
Therefore, the surface area of the rectangular pyramid with these measurements is 64yd^2.
None of the provided options (72.52y * d ^ 2, 55.55y * d ^ 2, 66y * d ^ 2, 43.31yd .^ 2) match the correct answer of 64yd^2.